The average acceleration is
[tex]\bar a=\dfrac{5\,\frac{\mathrm m}{\mathrm s}-0\,\frac{\mathrm m}{\mathrm s}}{4\,\mathrm s}=1.25\,\dfrac{\mathrm m}{\mathrm s^2}[/tex]
Answer:
The acceleration of the car is [tex]a=1.25\ m/s^2[/tex].
Explanation:
It is given that,
Initial speed of the car, u = 0
Final speed of the car, v = 5 m/s
Time, t = 4 s
We need to find the average acceleration over this period of time. It is given by the rate of change of velocity. It is given by :
[tex]a=\dfrac{v-u}{t}[/tex]
[tex]a=\dfrac{(5-0)\ m/s}{4\ s}[/tex]
[tex]a=1.25\ m/s^2[/tex]
So, the acceleration of the car is [tex]a=1.25\ m/s^2[/tex]. Hence, the correct option is (D).
