You have to solve h(t)=0 with the quadratic formula:
[tex] t = \frac{-46.7 \pm \sqrt{46.7^2-4\cdot -16 \cdot 0.5}}{2 \cdot -16} \approx 2.9294 [/tex]
So D is your answer (t=2.9)
It will take 2.9 seconds for the ball to hit the ground after it has been kicked.
A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.
A soccer player kicks a ball, and the height of the ball in feet as a function of time in seconds can be modeled by the function.
The given function is h(t) = –16t^2 + 46.7t + 0.5
The solution of the equation as follows
t = -b ± [tex]\sqrt{b^{2} - 4ac}[/tex] / 2a
t = - 46.7 ± √46.7^2 - 4(-16)(0.5) / 2(-16)
t = 2.928
Thus, It will take 2.9 seconds for the ball to hit the ground after it has been kicked.
Learn more about quadratic equations;
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