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The sum of two numbers is 24. Five times the first number minus the second number is 12. What are the two numbers?

Respuesta :

sayger

fist number 6

second number 18

6+18=24

6x5=30-18=12

The first number is 6 and the second number is 18.

Given to us,

Statement 1: sum of two numbers is 24,

Statement 2: Five times the first number minus the second number is 12.

Assumption

Let's assume the first number is x, and the second number is y.

Statement 1

Statement 1: sum of two numbers is 24,

[tex]x + y = 24\\y = 24 - x[/tex]

The above equation is equation 1, which also tells about the value y.

Statement 2

Statement 2: Five times the first number minus the second number is 12.

[tex]5x - y = 12[/tex]

substituting the value of y,

[tex]5x - (24 - x) = 12\\5x - 24 + x = 12\\6x = 12+24\\6x = 36\\\\x = \dfrac{36}{6}\\x= 6[/tex]

Now, substituting the value of x in equation 1,

[tex]y= 24-x\\y = 24-6\\y=18[/tex]

Hence, the first number is 6 and the second number is 18.

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