Solution:
we are given that
she wants to track to have a circumference of 150 feet.
we have been asked to find
what does the radius of the track need to be?
As we know that
[tex]Circumference=2\pi r[/tex]
Substitute the values we get
[tex]150=2 \pi r\\
\\
r=\frac{75}{\pi} \\
\\
r=\frac{75}{22/7}\\
\\
r=\frac{75*7}{22}= 23.863feet[/tex]
Hence radius=23.863 feet.
