Respuesta :

[tex] \bf 1.~(0,0)~\hspace{5em}0=\left( \cfrac{1}{2} \right)^0\implies 0\ne 1\qquad \otimes
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2.~\left( 0,\frac{1}{2} \right)~\hspace{5em}\cfrac{1}{2}=\left( \cfrac{1}{2} \right)^0\implies \cfrac{1}{2}\ne 1\qquad \otimes [/tex]


[tex] \bf 4.~(2,1)~\hspace{5em}1=\left( \cfrac{1}{2} \right)^2\implies 1=\cfrac{1^2}{2^2}\implies 1\ne \cfrac{1}{4}\qquad \otimes
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3.~\left(2,\frac{1}{4} \right)~\hspace{5em}\cfrac{1}{4}=\left( \cfrac{1}{2} \right)^2\implies \cfrac{1}{4}=\cfrac{1^2}{2^2}\implies \cfrac{1}{4}=\cfrac{1}{4}\qquad \checkmark [/tex]

MrRoyal

The point on a function are the true values of the function.

[tex]\mathbf{ (2,1/4)}[/tex] is a point on the graph of [tex]\mathbf{y = (\frac{1}{2})^x}[/tex]

The function is given as:

[tex]\mathbf{y = (\frac{1}{2})^x}[/tex]

[tex]\mathbf{1.\ (0,0)}[/tex]

This means that:

x = 0, and y = 0

So, we have:

[tex]\mathbf{0 = (\frac{1}{2})^0}[/tex]

[tex]\mathbf{0 = 1}[/tex]

The above is not true, because:

[tex]\mathbf{0 \ne 1}[/tex]

[tex]\mathbf{2.\ (0,1/2)}[/tex]

This means that:

x = 0, and y = 1/2

So, we have:

[tex]\mathbf{1/2 = (\frac{1}{2})^0}[/tex]

[tex]\mathbf{1/2 = 1}[/tex]

The above is not true, because:

[tex]\mathbf{1/2 \ne 1}[/tex]

[tex]\mathbf{3.\ (2,1/4)}[/tex]

This means that:

x =2, and y = 1/4

So, we have:

[tex]\mathbf{\frac 14 = (\frac{1}{2})^2}[/tex]

[tex]\mathbf{\frac 14 = \frac{1}{4}}[/tex]

The above is true.

Hence,

[tex]\mathbf{ (2,1/4)}[/tex] is a point on the graph of [tex]\mathbf{y = (\frac{1}{2})^x}[/tex]

Read more about points and graphs at:

https://brainly.com/question/20776528

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