Respuesta :
Alright, lets get started.
Please refer the diagram I have attached.
The angle between Melville Road and Emerson Avenue is 119°.
Hawthorne Lane bisects the angle formed by Melville Road and Emerson Avenue.
So, angle between Hawthorne Lane and Emerson Avenue will be = [tex] \frac{1}{2} * 119 = 59.5 [/tex]°
Now, angle between Emerson Avenue and Thoreau Street is 135°.
Dickinson Drive bisects the angle formed by Emerson Avenue and Thoreau Street.
So, angle between Dickinson Drive and Emerson Avenue will be = [tex] \frac{1}{2} * 135 = 67.5 [/tex]°
So, the complete angle between Hawthorne Lane and Dickinson Drive will be = [tex] 59.5 + 67.5 = 127 [/tex]°
So, the answer is 127 °. : Answer
Hope it will help :)

Answer:
the answer is 126.5
Step-by-step explanation:
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