Respuesta :
Answer : There are [tex]2.68\times 10^{24} molecules[/tex] in 100 Lof potassium hydroxide(KOH) solution at stp.
Explanation : To calculate the molecules we first need to find out the moles.
One mole of an ideal gas will occupy a volume of 22.4 liters at STP (Standard Temperature and Pressure, 0°C and one atmosphere pressure).
1 mole = 22.4 L
100 L = [tex](100 L)\times \frac{(1mole)}{(22.4 L)}[/tex]
100 L = [tex](100)\times \frac{(1mole)}{(22.4)}[/tex]
100 L = 4.46 mole potassium hydroxide(KOH)
Now , we need to convert 4.46 mole to molecules of KOH.
[tex]1 mole = 6.02\times 10^{23} molecules[/tex]
4.46 moles = [tex](4.46 mole)\times \frac{(6.02\times 10^{23}molecules)}{(1 mole)}[/tex]
4.46 moles = [tex](4.46)\times \frac{(6.02\times 10^{23}molecules)}{(1 )}[/tex]
4.46 moles = [tex]2.68\times 10^{24} molecules[/tex]
There are [tex]2.68\times 10^{24} molecules[/tex] in 100 Lof potassium hydroxide(KOH) solution at STP.
