The fraction for the determination of mass of Aluminum from known mass of aluminum chloride has been 2/2. Hence, option C is correct.
The mole ratio has been defined as the ratio of the moles of one substance with respect to the moles of another substance.
Mole ratio
The given reaction has been:
[tex]\rm Al\;+\;Cl_2\;\rightarrow\;AlCl_3[/tex]
For the determination of the mole ratio from the chemical reaction, the reaction has been balanced.
The balanced chemical reaction has been:
[tex]\rm 2\;Al\;+\;3\;Cl_2\;\rightarrow\;2\;AlCl_3[/tex]
From the balanced chemical equation, for 2 moles of aluminum chloride, 2 moles of Al have been used. Thus, the Al used for the x moles of known aluminum chloride has been:
[tex]\rm 2\;mol\;AlCl_3=2\;mol\;Al\\\textit x\;mol\;AlCl_3=\dfrac{2}{2}\;\times\;\textit x\;Al[/tex]
Thus, the fraction for the determination of mass of Aluminum from known mass of aluminum chloride has been 2/2. Hence, option C is correct.
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