On saturday, you bowl at mar vista bowl, where renting shoes costs $2 and each game bowled is $3.50. on sunday, you bowl at pinz where the shoe rental is $5 and each game bowled is $3.25. if you spent the same amount each day, how many games, g, were bowled?

Respuesta :

Given, at Mar Vista bowl the cost of renting shoes = $2.

The cost for each game bowled = $3.50

There are g games given. So the cost for g games bowled = $[tex] (3.50)(g) [/tex] = $[tex] (3.50g) [/tex]

The total amount soent at Mar Vista Bowl = $[tex] (2+3.50g) [/tex]

At Pinz, the cost for shoe rental = $5.

The cost for each game bowled = $3.25.

So the cost for g game bowled = $[tex] (3.25)(g) [/tex] = $[tex] (3.25g) [/tex]

Total amount spent at Pinz = $[tex] (5+3.25g) [/tex]

Given, the amount spent ateach of the places is same.

so we can write the equation as,

[tex] 2+3.50g = 5+3.25g [/tex]

We will move 3.25 to the left side by subtracting it from both sides. we will get,

[tex] 2+3.50g-3.25g = 5+3.25g-3.25g [/tex]

[tex] 2+0.25g = 5 [/tex]

Now we will move 2 to the right side by subtracting 2 from both sides. We will get,

[tex] 2+0.25g-2 = 5-2 [/tex]

[tex] 0.25g = 3 [/tex]

Now to get g we will divide 0.25 to both sides. We will get,

[tex] \frac{0.25g}{0.25}= \frac{3}{0.25}[/tex]

[tex] g =\frac{3}{0.25}[/tex]

[tex] g = 12 [/tex]

So we have got the required answer.

The number of games bowled = 12.