kinematic equation
v squared = u squared + 2 a x s
v= sq root (0 + 2 10 x 65)
i thimk
Explanation:
Given that,
Mass of the roller costar, m = 275 kg
It sits at the top of a hill with height 85 m, h = 85 m
We need to find the speed with which it is going when it reaches the bottom. It can be calculated using the conservation of energy as :
[tex]\dfrac{1}{2}mv^2=mgh[/tex]
g is the acceleration due to gravity
[tex]v=\sqrt{2gh}[/tex]
[tex]v=\sqrt{2\times 9.8\times 85}[/tex]
v = 40.81 m/s
So, the speed of the roller coaster when it reaches the bottom is 40.81 m/s. Hence, this is the required solution.
