Respuesta :
Answer;
= 305.911 g CO2
Explanation;
The equation for the reaction;
Fe2O3 + 3 CO → 2 Fe + 3 CO2
mole ratio;
3 mol CO2 are formed from 1 mole of Fe2O3
Moles of Fe2O3 = (370 g Fe2O3) / (159.6887 g Fe2O3/mol)
= 2.317 Moles
Moles of CO2
= 2.317 × (3 mol CO2 /1 mol Fe2O3) = 6.951 moles
Therefore;
= 6.951 moles × (44.00964 g CO2/mol) = 305.911 g CO2
=305.911 g CO2
The mass of the substance is the product of the moles and the molar mass. The number of grams of carbon dioxide formed from ferric oxide is 305.911 g.
What is mass in grams?
Mass is the amount of the substance or the molecule present in the given chemical compound. It can be given by the formula of the moles and the molar mass.
The chemical reaction can be shown as,
[tex]\rm Fe_{2}O_{3} + 3 CO \rightarrow 2 Fe + 3 CO_{2}[/tex]
The moles from the stoichiometry coefficient can be given as,
1 mole of [tex]\rm Fe_{2}O_{3}[/tex] = 3 mol [tex]\rm CO_{2}[/tex]
Calculate the moles of ferric oxide:
[tex]\begin{aligned}\rm Moles &= \rm \dfrac{mass}{\rm molar \;mass}\\\\&= \dfrac{370}{159.688}\\\\&= 2.31\;\rm moles\end{aligned}[/tex]
Calculate the moles of carbon dioxide:
[tex]\begin{aligned}\rm Moles &= \rm \dfrac{mass}{\rm molar \;mass}\\\\&= 2.31 \times \dfrac{3\;\rm mol \; CO_{2}}{1\;\rm mol \;Fe_{2}O_{3}}\\\\&= 6.95\;\rm moles\end{aligned}[/tex]
Hence,
[tex]\begin{aligned} &= 6.951\;\rm moles \times (44.00964 \;\rm g \;CO_{2}/mol)\\\\&=305.911 \;\rm g\; CO_{2} \end{aligned}[/tex]
Therefore, 305.911 gm is the mass of carbon dioxide.
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