1) Answer is: the concentration of potassium cations (K⁺) is 0.3 M.
Balanced chemical reaction (dissociation) of potassium sulfide in the water:
K₂S(aq) → 2K⁺(aq) + S²⁻(aq).
c(K₂S) = 0.15 M.
From balanced reaction: n(K₂S) : n(K⁺) = 1 : 2, because volume of the solution is constant: c(K⁺) = 2 · c(K₂S).
c(K⁺) = 0.3 M; concentration of potassium cations.
2) Answer is: its concentration is half that of the Cl⁻ ion.
Balanced chemical reaction (dissociation) of calcium chloride (CaCl₂) in the water:
CaCl₂(aq) → Ca²⁺(aq) + 2Cl⁻(aq).
From balanced reaction: n(Ca²⁺) : n(Cl⁻) = 1 : 2, because volume of the solution is constant: c(Ca²⁺) = c(Cl⁻) ÷ 2.
n is amount of the substance.
3) Answer is: 46.176 grams of Na₃PO₄ will be needed.
Balanced chemical reaction (dissociation) of sodium phosphate (Na₃PO₄) in the water:
Na₃PO₄(aq) → 3Na⁺(aq) + PO₄³⁻(aq).
V = 650 mL ÷ 1000 mL.
V = 0.650 L; volume of the solution.
c(Na⁺) = 1.3 M; concentratium of sodium cations.
From balanced reaction: n(Na₃PO₄) : n(Na⁺) = 1 : 3, because volume of the solution is constant: c(Na₃PO₄) = c(Na⁺) ÷ 3.
c(Na₃PO₄) = 1.3 M ÷ 3.
c(Na₃PO₄) = 0.43 M.
n(Na₃PO₄) = c(Na₃PO₄) · V(solution).
n(Na₃PO₄) = 0.43 M · 0.65 L.
n(Na₃PO₄) = 0.281 mol.
m(Na₃PO₄) = n(Na₃PO₄) · M(Na₃PO₄).
m(Na₃PO₄) = 0.281 mol · 163.94 g/mol.
m(Na₃PO₄) = 46.176 g.
1. Concentration K⁺ = [K⁺] = 0.3 M
2. Ca²⁺concentration is half that of the Cl⁻ ion.
3. 45,838 grams of Na₃PO₄ will be needed
Stokiometry in Chemistry studies about chemical reactions mainly emphasizing quantitative, such as the calculation of volume, mass, amount, which is related to the number of ions, molecules, elements, etc.
Reaction equations are chemical formulas for reagents and product substances
Reaction coefficients are numbers in the chemical formula of substances involved in the reaction equation. Reaction coefficients are useful for balancing reagents and products.
The reaction coefficient shows the ratio of the number of moles or molecules of the reacting substance
The ionization reaction is the reaction of the decomposition of a substance into its ions when the substance is dissolved in water.
Molarity (M)
Molarity shows the number of moles of solute in every 1 liter of solution.
[tex]\large {\boxed{\bold {M ~ = ~ \frac {n} {V}}}[/tex]
Where
M = Molarity
n = Number of moles of solute
V = volume of the solution
K₂S(aq) ----> 2K⁺ (aq) + S²⁻ (aq)
Comparison of reaction coefficients = mole ratio = concentration ratio for the same volume, so
K₂S coefficient: coefficient 2K⁺ = 1: 2
[K⁺] = 2. [K₂S]
[K⁺] = 2. 0.15 M
[K⁺] = 0.3 M
CaCl₂ -> Ca²⁺ + 2Cl⁻
Same as the explanation in point 1:
coefficient Ca²⁺: coefficient Cl⁻= 1: 2
so that
[Ca²⁺] = 1/2 [Cl⁻]
[Ca²⁺] half of the concentration [Cl⁻]
Na₃PO₄ ---> 3Na + + PO₄³⁻
[Na₃PO₄] = 1/3. [Na +]
[Na₃PO₄] = 1/3. 1.3
[Na₃PO₄] = 0.43 M
then the number of moles is
mol = M. vol
mole = 0.43. 0.65 L
mole = 0.2795
So that its mass:
molar mass of Na₃PO₄ = 164 g / mol
mass = mole. molar mass
mass = 0.2795. 164
mass = 45,838 grams
grams of hydrogen
https://brainly.com/question/4277430
grams of calcium chloride
https://brainly.com/question/9945440
sample of H₃PO₄ solution
https://brainly.com/question/9850829
Keywords: ionization, molar mass, mole, mass, Na₃PO₄, K₂S, CaCl₂
