Answer is: the molecular formula is C₆H₁₀.
Chemical reaction: C₆Hₓ + yO₂ → 6CO₂ + x/2H₂O.
m(H₂O) = 0.9102; mass of the water.
n(H₂O) = m(H₂O) ÷ m(H₂O)
n(H₂O) = 0,9102 g ÷ 18 g/mol
n(H₂O) = 0,0505 mol.
From chemical reaction: n(H) = 2 · n(H₂O).
n(H) = 0.101 mol.
m(CO₂) = 2.668 g; mass of carbon dioxide.
n(CO₂) = 2.668 g ÷ 44 g/mol.
n(CO₂) = 0.0606 mol; amount of the substance.
n(CO₂) = n(C) = 0.0606 mol.
n(C) : n(H) = 0.606 mol : 0.101 mol.
n(C) : n(H) = 6 : 10; proportion of carbon and hydrogen atoms in cyclohexene.
Answer:
Explanation;
Given Data:
Solution:
% of C = (mass of CO2/mass of compound)× (12/44)×100
% of C = (2.66÷0.8300)×(12/44)× 100 = 87.40 %
% of H = (mass of H2O/mass of compound)× (2/18)×100
% of H = (0.910÷0.8300)× (2/18)×100 = 12.18 %
Niiw we calculate moles of C and H from % as follow
moles of C = 87.40/12 = 7.2 mol
moles of H = 12.18/1 = 12.18 mol
In we take atomic ratio
C : H
12.18/7.2 : 7.2/7.2
1.69 : 1
multiply atomic ratio by 3 to get whole no.
C : H = 3 (1.69:1) = 5 : 3
So empirical formula is C3H5.
Calculations of molecular formula:
empirical formula mass of C3H5 = 41
n = molar mass of compound /empirical formula mass
n = 82.1/41 = 2
Molecular mass = n × empirical formula = 2 × C3H5 = C6H10
