2S+3O2 -> 2SO3 Indicate whether S or O2 is the limiting reactant, 3mol S 4mol O, 3mol S 5mol O, 3mol S 3mol? Elemental S reacts with O2 to form SO3 according to the reaction 2S+3O2 ---> 2SO3 For each of the given situations, indicate whether S or O2 is the limiting reactant.

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Dejanras Dejanras · Answer 1 · 2018-09-30T11:36:26+02:00

Balanced chemical reaction: 2S + 3O₂ → 2SO₃.

1) Answer is: oxygen is limiting reactant.

n(S) = 3 mol; amount of sulfur.

n(O₂) = 4 mol; amount of oxygen.

From balanced chemical reaction: n(S) : n(O₂) = 2 : 3.

3 mol : n(O₂) = 2 : 3.

n(O₂) = (3 · 3 mol) ÷ 2.

n(O₂) = 4.5 mol; limiting reactant, because there is only 4 mol of oxygen.

2) Answer is: sulfur(S) is limiting reactant.

n(S) = 3 mol.

n(O₂) = 5 mol.

From balanced chemical reaction: n(S) : n(O₂) = 2 : 3.

n(S) : 5 mol = 2 : 3.

n(S) = 10 mol ÷ 3.

n(S) = 3.33 mol; there is only 3 mol of sulfur, so it is not enough.

3) Answer is: oxygen (O₂) is limiting reactant.

n(S) = 3 mol.

n(O₂) = 3 mol.

From balanced chemical reaction: n(S) : n(O₂) = 2 : 3.

3 mol : n(O₂) = 2 : 3.

n(O₂) = (3 · 3 mol) ÷ 2.

n(O₂) = 4.5 mol; limiting reactant, because there is only 3 mol of oxygen.

Oseni Oseni · Answer 2 · 2021-11-11T15:24:08+01:00

From the balanced equation of the reaction:

[tex]2S+3O_2 ---> 2SO_3[/tex]

The ratio of S to O2 is 2:3. Hence, for every 1 mole of S, 1.5 moles of O2 must be used.

For 3 moles of S, 4.5 moles of O2 must be used.

Hence,

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