Which of these units results when a distance of 35 m is multiplied by a force of 27 n, and then divided by a time of 5s? a newtom n is kg * m/s2 in si base units?

Respuesta :

Answer:

SI unit for Joule per second is [tex]\frac{kg m^{2} }{s^{2} }[/tex].

Explanation:

When a distance of 35 m is multiplied by a force of 27 N.

Force × distance = 27 N × 35 m = 945 Joule

945 Joule = 945 [tex]\frac{kg m}{s^{2} } \times m[/tex]

945 joule = 945 [tex]\frac{kg m^{2} }{s^{2} }[/tex]

This is SI unit for force multiplied by distance.

The above quantity is divided by 5 s.

[tex]\frac{945}{5} \frac{Joule}{s}[/tex] = 189 [tex]\frac{kg m^{2} }{s^{3} }[/tex]

SI unit for Joule per second is [tex]\frac{kg m^{2} }{s^{2} }[/tex].

Answer:

[tex]\frac{F \times d}{t} = 189 \frac{kg m^2}{s^3}[/tex]

Explanation:

Here first we multiplied the force with the distance so we have

F = 27 N

distance = 35 m

so the product is given as

[tex]F\times d = 27 N \times 35 m[/tex]

[tex]F\times d = 945 N m[/tex]

now we have to divide it by time

so we have

[tex]\frac{F \times d}{t} = \frac{945}{5}[/tex]

[tex]\frac{F \times d}{t} = 189 Nm/s[/tex]

so it is

[tex]\frac{F \times d}{t} = 189 \frac{kg m^2}{s^3}[/tex]