Respuesta :
Answer:
SI unit for Joule per second is [tex]\frac{kg m^{2} }{s^{2} }[/tex].
Explanation:
When a distance of 35 m is multiplied by a force of 27 N.
Force × distance = 27 N × 35 m = 945 Joule
945 Joule = 945 [tex]\frac{kg m}{s^{2} } \times m[/tex]
945 joule = 945 [tex]\frac{kg m^{2} }{s^{2} }[/tex]
This is SI unit for force multiplied by distance.
The above quantity is divided by 5 s.
[tex]\frac{945}{5} \frac{Joule}{s}[/tex] = 189 [tex]\frac{kg m^{2} }{s^{3} }[/tex]
SI unit for Joule per second is [tex]\frac{kg m^{2} }{s^{2} }[/tex].
Answer:
[tex]\frac{F \times d}{t} = 189 \frac{kg m^2}{s^3}[/tex]
Explanation:
Here first we multiplied the force with the distance so we have
F = 27 N
distance = 35 m
so the product is given as
[tex]F\times d = 27 N \times 35 m[/tex]
[tex]F\times d = 945 N m[/tex]
now we have to divide it by time
so we have
[tex]\frac{F \times d}{t} = \frac{945}{5}[/tex]
[tex]\frac{F \times d}{t} = 189 Nm/s[/tex]
so it is
[tex]\frac{F \times d}{t} = 189 \frac{kg m^2}{s^3}[/tex]