Respuesta :
as it is given that curved marked the speed as v = 70 km/h
so we will first convert the speed into m/s
[tex]v = 70 km/h = 19.44 m/s[/tex]
now we know that here friction force will provide centripetal force
[tex]F_c = F_f[/tex]
As we know that centripetal force is given as
[tex]F_c = \frac{mv^2}{R}[/tex]
[tex]\frac{mv^2}{R} = \mu_k mg[/tex]
[tex]\frac{v^2}{R} = \mu_k g[/tex]
[tex]v^2 = \mu_k R * g[/tex]
[tex]19.44^2 = 0.5* R * 9.8[/tex]
[tex]378 = 4.9 * R[/tex]
[tex]R = 77.1 m[/tex]
Answer:
54.86 m
Explanation:
The radius of curvature for a curve marked can be calculated by equating centripetal force and force of frcition.
[tex]\frac{mv^2}{r}=\mu mg\\ \Rightarrow \frac{v^2}{r} = \mu g\\ \Rightarrow r = \frac{v^2}{\mu g}[/tex]
v = 70 km/h = 19.4 m/s
Substitute the values:
[tex]r = \frac{(19.4 m/s)^2}{(0.7) (9.8m/s^2)}=54.86 m[/tex]
