Respuesta :
The balanced chemical reaction of Zn with HCl is
Zn + 2HCl --> ZnCl2 + H2(g)
So here one mole of Zn reacts with two moles of HCl
Moles of Zn = mass of Zn / atomic mass of Zn = 2.25 / 65.38 = 0.0344
so moles of HCl reacted = 2 X moles of Zn = 2 X 0.0344 = 0.0688
Moles = molarity X volume
Therefore
Volume = moles / molarity = 0.0688 / 3.50 = 0.019657 L = 19.657 mL
In a combination reaction of zinc and hydrochloric acid, zinc chloride and hydrogen gas is produced. The volume of the HCl required to react with zinc is 19.657 mL.
What is a combination reaction?
A combination reaction is a type of chemical reaction in which the reactants combines to form two or more products. Here zinc and hydrochloric acid reacted to yield hydrogen and zinc chloride.
The chemical reaction can be shown as,
[tex]\rm Zn + 2HCl \rightarrow ZnCl_{2} + H_{2}(g)[/tex]
From the reaction, it can be said that 1 mole of Zinc reacted with 2 moles of hydrochloric acid.
Calculate moles of zinc:
[tex]\begin{aligned} \rm moles &= \dfrac{\rm mass}{\rm molar\; mass}\\\\&= \dfrac{2.25}{65.38}\\\\&= 0.0344 \;\rm moles \end{aligned}[/tex]
Moles of HCl reacted will be:
[tex]2 \times 0.0344 = 0.0688 \;\rm moles[/tex]
Volume can be calculated as:
[tex]\begin{aligned}\rm volume &= \dfrac{\rm moles}{\rm molarity}\\\\&= \dfrac{0.0688}{3.50}\\\\&= 19.65 \;\rm mL\end{aligned}[/tex]
Therefore, 19.65 mL is the volume of the acid required.
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