We are given number : 5,336.
Let us expand this number by writing place value of each digit to understand the problem better.
5 is at thousands place. Tharefore 5 x 1,000.
3 is at hundreds place. Tharefore 3 x 100.
3 is at tens place. Tharefore 3 x 10.
6 is at ones place. Tharefore 6 x 1.
Therefore, 5,336 = 5,000+ 300 + 30 + 6.
Now, we need to find the digits in which one digit is 10 times as great as the other.
Let us observe 300 and 30 there.
We can see that 300 is 10 times of 30.
Therefore, 3 are the digits in which one digit is 10 times as great as the other.
