Respuesta :
Let the integers be x and x+2. then:-
x + 2 = 2x - 6
x = 8
The integers are 8 and 10 Answer
Two consecutive integers can be written as [tex] x [/tex] and [tex] x+1 [/tex].
So, six less than twice the smaller is [tex] 2x-6 [/tex], and this equals the greater, which is [tex] x+1 [/tex]. So the equality is
[tex] 2x - 6 = x+1 [/tex]
Subtract x from both sides:
[tex] x-6 = 1 [/tex]
Add 6 to both sides:
[tex] x = 7 [/tex]
So, the integers are 7 and 8. In fact, the greater (8) is six less than twice the smaller (2*7-6 = 14-6=8)
