Respuesta :

kudzordzifrancis

In order to determine which subset it belongs, we must rewrite

[tex]\sqrt(30)[/tex]

as

[tex]\sqrt(30)=\sqrt(2\times \times 3 \times 5)[/tex]


[tex]\Rightarrow \sqrt(30)=\sqrt(2 \times 3\times 5)[/tex]

[tex]\Rightarrow \sqrt(30)=\sqrt(2) \times \sqrt(3) \times \sqrt(5)[/tex]


All these three numbers are irrational numbers, hence their product is also irrational


[tex]\Rightarrow \sqrt(30)[/tex]

belongs to the set of irrational numbers

lublana

Answer:

Irrational number

Step-by-step explanation:

We are given that [tex]\sqrt{30}[/tex]

We have to find that given  number from which subset of real numbers  belong.

[tex]\sqrt{30}[/tex]  can be written as

[tex]\sqrt{30}=\sqrt2\times \sqrt3\times \sqrt{5}[/tex]

We know that

[tex] \sqrt2, \sqrt3,\sqrt5[/tex] are irrational numbers .

Product of irrational numbers sometimes rational and some times irrational depend upon given numbers.

Therefore, [tex]\sqrt{30}[/tex] is a irrational number.

Hence, [tex]\sqrt{30}[/tex] belongs to irrational number .