Respuesta :
The concentration of each of the individual ions in a 0750 M Ba(OH)2 solution is
[Ba2+] = 0.750 M
[OH-]= 1.50 M
calculation
write the equation for dissociation
that is Ba(OH)2 (s)→ Ba2+(aq) + 2OH-(aq)
by use of mole ratio of Ba(OH)2 : Ba2+ which is 1: 1 the concentration of Ba2+ is therefore= 0.750M
by use of mole ratio of Ba(OH)2 : OH- which is 1:2 the concentration of OH- =0.750 M x2/1=1.50 M
The concentration of each of the individual ions in a 0750 M Ba(OH)2 solution is [tex]Ba_2+[/tex] = 0.750M and [tex]OH^-[/tex] = 1.50 M.
What is an electrolyte?
An electrolyte is a medium that contains ions and conducts electricity by the diffusion of ions, but not electrons.
Most acids, and bases, soluble salts dissolved in a polar solvent, such as water, fall into this category.
Given,
[[tex]Ba_2+[/tex]] = 0.750 M
[[tex]OH^-[/tex]]= 1.50 M
The equation for dissociation is:
[tex]Ba(OH)^2 (s) = Ba^2+(aq) + 2OH-(aq)[/tex]
By using the mole ratio of [tex]Ba(OH)^2[/tex]: [tex]Ba_2+[/tex] which is 1: 1 the concentration of [tex]Ba_2+[/tex] is = 0.750M
By using the mole ratio of [tex]Ba(OH)^2[/tex]: [tex]OH^-[/tex] which is 1:2 the concentration of [tex]OH^-[/tex] [tex]=0.750 M \times\dfrac{2}{1} =1.50\; M[/tex]
Thus, the concentration of individual ions is [tex]Ba_2+[/tex] = 0.750M and [tex]OH^-[/tex] = 1.50 M.
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