Respuesta :


The concentration of each of the individual ions in a 0750 M Ba(OH)2 solution is

[Ba2+] = 0.750 M

[OH-]= 1.50 M

calculation

write the equation for dissociation

that is  Ba(OH)2  (s)→ Ba2+(aq)  + 2OH-(aq)

by use of mole ratio of Ba(OH)2 : Ba2+ which is 1: 1 the concentration of Ba2+ is therefore= 0.750M

by use of mole ratio of Ba(OH)2 : OH- which is 1:2 the concentration of  OH- =0.750 M x2/1=1.50 M

The concentration of each of the individual ions in a 0750 M Ba(OH)2 solution is  [tex]Ba_2+[/tex] = 0.750M and [tex]OH^-[/tex] = 1.50 M.

What is an electrolyte?

An electrolyte is a medium that contains ions and conducts electricity by the diffusion of ions, but not electrons.

Most acids, and bases, soluble salts dissolved in a polar solvent, such as water, fall into this category.

Given,

[[tex]Ba_2+[/tex]] = 0.750 M

[[tex]OH^-[/tex]]= 1.50 M

The equation for dissociation is:

[tex]Ba(OH)^2 (s) = Ba^2+(aq) + 2OH-(aq)[/tex]

By using the mole ratio of [tex]Ba(OH)^2[/tex]: [tex]Ba_2+[/tex] which is 1: 1 the concentration of [tex]Ba_2+[/tex] is = 0.750M

By using the mole ratio of [tex]Ba(OH)^2[/tex]: [tex]OH^-[/tex] which is 1:2 the concentration of  [tex]OH^-[/tex] [tex]=0.750 M \times\dfrac{2}{1} =1.50\; M[/tex]

Thus, the concentration of individual ions is [tex]Ba_2+[/tex] = 0.750M and [tex]OH^-[/tex] = 1.50 M.

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