Iron sulfate can be shown as FeSO4 and the number mole of FeSO_4 can be determined as
Molar mass of Iron sulfate = 151 g /mole
Mass of Iron sulfate = 10 g
[tex]Mole = mass /molar mass
\\ = 10 /151 = 0.066 mol[/tex]
Number of Fe ion can be determined as
[tex]Mole = Number of ion / Avogadro number
\\ 0.066 = Number of ion / 6.02 * 10^23
\\ Number of ion = 3.98 * 10^22[/tex]
Thus, [tex]3.98 * 10^22[/tex] ions are present in Iron sulfate
The number of Fe(ii) ions that are in 10.0g of FeSO4 is 3.961 x10^22 ions
calculation
find the number of moles of FeSO4 = mass/molar mass
= 10g / 151.9 g/mol=0.0658 moles since there 1 atom of fe the moles of Fe= 0.0658 moles
by use of Avogadro's constant
that is 1 mole= 6.02 x10^23 ions
0.0658moles=? ions
= 0.0658 mole x(6.02 x10^23)] / 1 mole = 3.961 x10^22 ions
