Answer-
The rider’s displacement during this time is 17.01 m
Solution-
As we know,
[tex]s= ut + \frac{1}{2}at^{2}[/tex]
Where s = displacement,
u= initial velocity = 0, as the rider starts from rest
a= acceleration = 0.5 m/s²
t= time taken = 8.4 s
Putting the values,
[tex]s = (0)(8.4) + \frac{1}{2} (0.5)(8.4)^{2} = 17.64 \ m[/tex]
Answer:
Step-by-step explanation:
a=0.50
t=8.4s
initial velocity=0
0+1/2*0.50*8.4^2=17.64m
17.6
