Respuesta :
[tex]E_i1[/tex] will be largest for [tex]1s^22s^22p^63s^23p^5[/tex].
Explanation: Ionization energy is the energy to knock off an electron from a gaseous atom of ion. First ionization energy or [tex]E_i1[/tex] is the energy required to remove 1 loosely held electron from 1 mole of gaseous atoms to produce 1 mole of gaseous ion carrying (+)1 charge.
[tex]M(g)\rightarrow M^+(g)+e^-[/tex]
The electrons are filled according to Aufbau's rule and the orbitals which are strongly held to the nucleus follows the order [tex]s>p>d>f[/tex].
Electron is released from the outermost shell that is from the electrons which are loosely held to the nucleus, this follows the pattern [tex]s<p<d<f[/tex].
In configurations, [tex]1s^22s^22p^63s^23p^64s^1,1s^22s^22p^63s^23p^5\text{ and } 1s^22s^22p^63s^23p^1[/tex]
The loosely held orbital is 4s, therefore electron will be lost from that easily.
Now, in 3p orbital, one configuration has 5 electrons and one has 1 electron.
The configuration having 5 electrons will be more tightly held by the nucleus because it has more electrons that the one having only 1 electron. Hence, the electron will be lost easily from the configuration having [tex]3p^1[/tex] as the valence shell.
Therefore, the configuration [tex]1s^22s^22p^63s^23p^5[/tex] will the largest [tex]E_i1[/tex].
