Solution:
[tex]\hbox{Let the distribution standarized is z}\\ \hbox{given:-}\mu =50\hbox{ and} \sigma =6\hbox{will become
} \mu=50 \hbox{ and} \sigma =10\\\hbox{distribution standarized with value x=52 }\\\rm{so}\\\hbox{the value of score is:}\\z=\frac{x-\mu }{\sigma}\\\rm{if}\\p(x< 52)=p(z<-0.5 )\\\rm{thus}\\\hbox{new is}z=\frac{50-10 }{2}=45\\\hbox{this the required right answer}[/tex]
What value will be obtained for a score of x is mathematically given as
z=45
Question Parameters:
A distribution with µ = 55 and σ = 6
he new mean and standard deviation will be µ = 50 and σ = 10.
What value will be obtained for a score of x = 52
Generally the equation for the value of score z is mathematically given as
[tex]z=(x-\mu)/\sigma[/tex]
Therefore
z=(50-10)/ 2
z=45
where
p(x<52)=p(z<-0.5)
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