The flight is in the shape of a parabola with a vertex 5 feet above the water and 1/2 * 33 = 16.5 feet horizontally from the point of leaving the water
y = a(x - h)^2 + k
where (h,k) is the vertex of the parabola and here it is (5 , 16.5), so we have the function:-
y = a(x - 16.5)^2 + 5
when x = 0 y = 0 so
0 = a(-16.5)^2 + 5
which gives a = -0.018365
So our function for the flight path is
y = -0.018365(x - 16.5)^2 + 5 Answer
Answer:
Equation: [tex]y= -0.00459*(x-33)^{2} + 5[/tex]
Step-by-step explanation:
Using the value as height in axis y, and horizontal distance in axis x
[tex]y=a*(x-h)^{2}+k\\ h=33\\k=5\\y=a*(x-33)^{2}+5[/tex]
X=0, Y=0
[tex]y=a*(x-33)^{2}+5\\ 0=a*(0-33)^{2}+5\\a=-\frac{5}{33^{2} } =-0.00459[/tex]
In the figure can see the motion of the fish while flying like airplane
