Answer:
-54 J
Explanation:
Here we have to use the specific heat equation,
Q = mc∆T
where Q is the heat, m is the mass, c is the specific heat capacity and ∆T is the change of temperature.
Given,
m = 12 g
c = 2.5 J/g⋅°C
∆T = Tfinal - Tinitial = 36.7 °C - 38.5 °C = -1.8 °C
Plugging the numbers in the specific heat equation,
Q = 12 g x 2.5 J/g⋅°C x - 1.8 °C = -54 J
As heat is released Q has a negative sign. When heat is absorbed Q has a positive sign.
