Answer:
Cat has 2.02 seconds to right itself.
Explanation:
Initial height of cat from ground = 20 meter.
We have equation of motion , [tex]s= ut+\frac{1}{2} at^2[/tex], s is the displacement, u is the initial velocity, a is the acceleration and t is the time.
In this the velocity of cat in vertical direction = 0 m/s, acceleration = acceleration due to gravity = 9.8 [tex]m/s^2[/tex], we need to calculate time when s = 20 meter.
Substituting
[tex]20=0*t+\frac{1}{2} *9.8*t^2\\ \\ t = 2.02 seconds[/tex]
So, cat has 2.02 seconds to right itself.
