Respuesta :

TPS00

[tex]x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x = \frac{8 \pm \sqrt{ {8}^{2} - 4 \times 2 \times 5 } }{2 \times 2} [/tex]

[tex]x = \frac{8 \pm \sqrt{24} }{4} \\ \\ x = \frac{8 \pm2 \sqrt{6} }{4} [/tex]

[tex]x = 2 \pm \frac{ \sqrt{6} }{2} \\ \\ x = 2 \pm \sqrt{1.5} \\ \\ x = 2 + \sqrt{1.5} \: \: and \: \: \: 2 - \sqrt{1.5} [/tex]

[tex]\textbf{\red{Your answers are correct.}} [/tex]