Answer:
Deceleration value of motorcycle = [tex]6.83 m/s^2[/tex]
Explanation:
We have equation of motion, [tex]v^2=u^2+2as[/tex], where u is the initial velocity, v is the final velocity, s is the displacement and a is the acceleration.
In this case we have final velocity = 0 m/s, initial velocity = 32 m/s, and displacement = 75 m, now we need to find deceleration value.
Substituting
[tex]0^2 = 32^2+2*a*75\\ \\ a = -6.83 m/s^2[/tex]
So, Acceleration value of motorcycle = [tex]-6.83 m/s^2[/tex]
Deceleration value of motorcycle = [tex]6.83 m/s^2[/tex]
