Nancy took a 3-hour drive. She went 50 miles before she got caught in a storm. Then, she drove 68 miles at 9 mph less than she had driven when the weather was good. What was her speed driving in the storm?

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Answer:    

Speed in the storm is 36 miles per hour.

Step-by-step explanation:

Given : Nancy took a 3-hour drive. She went 50 miles before she got caught in a storm. Then, she drove 68 miles at 9 mph less than she had driven when the weather was good.

To find : What was her speed driving in the storm?

Solution :

The relation between speed, distance and time is

[tex]\text{Distance}=\text{Speed}\times\text{Time}[/tex]

Let s be the speed in the storm, miles per hour

When there is no storm.

Speed = s+9 miles per hour

Distance = 50 miles

Time is [tex]T=\frac{D}{S}=\frac{50}{s+9}[/tex]

When there is storm

Speed = r

Distance = 68 miles

Time is [tex]T=\frac{68}{s}[/tex]

Total time taken = 3 hour

Therefore, In the journey total time is

[tex]\frac{50}{s+9}+\frac{68}{s}=3[/tex]

Solving the equation,

[tex]\frac{50s+68(s+9)}{s(s+9)}=3[/tex]

[tex]\frac{50s+68s+612}{s^2+9s}=3[/tex]

[tex]118s+612=3s^2+27s[/tex]

[tex]3s^2-91s-612=0[/tex]

Solving the quadratic equation by middle term split,

[tex]3s^2+17s-108s-612=0[/tex]

[tex]s(3s+17)-36(3s+17)=0[/tex]

[tex](s-36)(3s+17)=0[/tex]

[tex](s-36)=0,(3s+17)=0[/tex]

Either s=36 or s=-17/3

Speed is not negative

Therefore, s=36 mph

Speed in the storm is 36 miles per hour.

The speed of Nancy driving in the storm is [tex]\boxed{36{\text{ mph}}}.[/tex]

Further explanation:

The formula for speed is given as,

[tex]\boxed{s = \dfrac{d}{t}}[/tex]

Here, [tex]s[/tex] represents the speed, [tex]d[/tex] represents the distance, and [tex]t[/tex] represents time.

Given:

Nancy drove 50 miles in the good weather and she doves 68 miles in the storm.

She took 3 hour drive.

Calculation:

Consider the speed of Nancy in good weather be [tex]x+9{\text{ mph}}.[/tex]

The speed of Nancy in storm will be [tex]\left({x }\right){\text{ mph}}.[/tex]

The formula for time can be expressed as,

[tex]\boxed{{\text{Time}}=\frac{{{\text{distance}}}}{{{\text{speed}}}}}[/tex]

The time taken to drive 50 miles in good weather can be calculated as follows,

[tex]{t_1} = \dfrac{x+9}{{50}}[/tex]

The time taken to drive 68 miles in storm can be calculated as follows,

[tex]{t_2} = \dfrac{{x}}{{68}}[/tex]

The total time t is the sum of [tex]{t_1}[/tex] and [tex]{t_2}.[/tex]

[tex]\begin{aligned}3&=\frac{{50}}{{x + 9}}+\frac{{68}}{x}\\3&= \frac{{50x + 68x + 612}}{{x\left( {x + 9}\right)}}\\3&=\frac{{50x + 68x + 612}}{{{x^2} + 9x}}\\3\times \left( {{x^2} + 9x} \right)&= 118x + 612\\3{x^2} + 27x&= 118x + 612\\3{x^2} - 91x - 612&=0\\\end{aligned}[/tex]

Further solve the above equation.

[tex]\begin{aligned}3{x^2} + 17x - 108x - 612&= 0\\x\left( {3x + 17} \right) - 36\left( {3x + 17}\right)&= 0\\\left( {x - 36} \right)\left( {3x + 17} \right)&= 0\\\end{aligned}[/tex]

The speed in the storm can be obtained as follows,

[tex]\begin{aligned}x - 36&=0\\x&=36\\\end{aligned}[/tex]

Neglect the second value of x as the speed cannot be negative.

The speed of Nancy driving in the storm is [tex]\boxed{36{\text{ mph}}}.[/tex]

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Answer details:

Grade: High School

Subject: Mathematics

Chapter: Linear equation

Keywords: Felicia, home, Ferrari, Rome, Sorrento, average, returning, Capri, boat, average speed, far, distance, speed, time, returning, averaged, 60 mph.