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one car travels 50 miles per hour and another one travels at 55 miles per hour. they start atbthe same point ans at the same time in the dame direction, after how many hours will the faster car be 35 mikes ahead of the slower car.

Respuesta :

altavistard

Think:  (distance traveled by faster car) - (distance traveled by slower car) = 35 mi.

Using the formula distance = rate times time, we get for the faster car:

(55 mph)(t)

and for the slower car we get (50 mph)(t), so that

(55 mph)(t) - (50 mph)(t) = 35 mi.  This can be simplified as follows:

(5 mph)(t) = 35 mi.  Dividing both sides by 5 mph, we get t = (35 mi) / (5 mph).

Then t = 7 hours.  The two cars will be 35 miles apart, going in the same direction, after  7 hours.


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