Find the coordinates of the points of intersection of the graph of y=13−x with the axes and compute the area of the right triangle formed by this line and coordinate axes.

Respuesta :

The x- and y-intercepts are both 13, so the area is ...

... A = (1/2)bh = (1/2)·13·13 = 169/2 = 84.5 . . . square units

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Solve for x when y=0 to find the x-intercept:

... 0 = 13 - x

... x = 13 . . . . . add x

Solve for y when x=0 to find the y-intercept:

... y = 13 - 0

... y = 13 . . . . . additive identity property of 0

Ver imagen sqdancefan

The point at which two lines meet is referred to as the point of intersection.

  • The point of intersection with the y-axis is: [tex](0,13)[/tex].
  • The point of intersection with the x-axis is: [tex](13,0)[/tex].
  • The area of the triangle is 84.5 square units

The linear equation is given as:

[tex]y = 13 - x[/tex]

Intersection with the y-axis

Set [tex]x=0[/tex],

[tex]y = 13 - x[/tex]

[tex]y = 13 - 0[/tex]

[tex]y = 13[/tex]

This means that: [tex]y = 13 - x[/tex] intersects with the y-axis at: [tex](0,13)[/tex]

Intersection with the x-axis

Set [tex]y=0[/tex],

[tex]y = 13 - x[/tex]

[tex]0 = 13 - x[/tex]

[tex]x = 13[/tex]

This means that: [tex]y = 13 - x[/tex] intersects with the x-axis at: [tex](13,0)[/tex]

The area of the right-angled triangle

The area is calculated as:

[tex]Area = 0.5 \times Base \times Height[/tex]

In this case,

[tex]Base = x[/tex]

[tex]Height = y[/tex]

So, we have:

[tex]Area = 0.5 \times x \times y[/tex]

This gives:

[tex]Area = 0.5 \times 13 \times 13[/tex]

[tex]Area = 84.5[/tex]

Hence, the area of the triangle is 84.5 square units

See attachment for the graph of   [tex]y = 13 - x[/tex]

Read more about graphs at:

https://brainly.com/question/11897796

Ver imagen MrRoyal