2/3
there are a total of 3 + 4 + 2 = 9 spaces of which 2 are green and 4 are blue
P( green)= [tex]\frac{2}{9}[/tex] and P( blue) = [tex]\frac{4}{9}[/tex]
P( green or blue ) = P(green) + P(blue) = [tex]\frac{2}{9}[/tex] + [tex]\frac{4}{9}[/tex] = [tex]\frac{6}{9}[/tex] = [tex]\frac{2}{3}[/tex]