Answer:
6.75 in
Step-by-step explanation:
We are given that
Area of piece of construction paper=[tex]65\frac{1}{4} in^2=\frac{261}{4} in^2[/tex]
Length of piece of construction paper=[tex]9\frac{2}{3} in=\frac{29}{3}in[/tex]
We have to find the width of a piece of construction paper.
Width of rectangle =[tex]\frac{Area}{length}[/tex]
Width of piece of construction paper=[tex]\frac{\frac{261}{4}}{\frac{29}{3}}[/tex]
Width of piece of construction paper=[tex]\frac{261}{4}\times \frac{3}{29}=\frac{27}{4}=6.75in[/tex]
Hence, width of piece of construction paper=6.75 in
