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on earth a block is placed on a frictionless table. When a 50 North horizontal force is applied to the block, it accelerates at 4.0 m / s squared. Supposed to block and table are set up on the moon. When a horizontal force of 25 n is applied to the block what is the acceleration

Respuesta :

As per Newton's II law we know that

[tex] F = ma[/tex]

here

F = applied unbalanced force

m = mass of object

a = acceleration of object

now it is given that force F = 50 N North applied on block on earth due to which block will accelerate by 4 m/s^2

so here from above equation

[tex]50 = m* 4[/tex]

[tex]m = \frac{50}{4} = 12.5 kg[/tex]

Now we took another situation where block is placed on surface of moon and again force F = 25 N is applied on the block

So we will again use Newton's II law

[tex]F = ma[/tex]

[tex]25 = 12.5 * a[/tex]

[tex] a = \frac{25}{12.5}[/tex]

[tex]a = 2 m/s^2[/tex]

so block will accelerate on moon by acceleration 2 m/s^2

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