Answer is C, I just answered the question in my Lesson and got it right. Hope it helps :)
Answer:
Answer is option C (5.0 x 10^22 carbon atoms)
Explanation:
To solve this exercise we need to use stoichiometric relations to relate grams of Carbon with atoms of Carbon. These relations are:
a) 1 mol of Carbon atoms = 12 g C (atomic weight of C taken from periodic table)
b) 1 mol of Carbon atomos = 6,022 x 10*23 Carbon atomos (this number is the Avogadros number)
So we will use these two relation to transform grams of Carbon to atoms of Carbon. We will follow this structure:
Unknown variable = Data x "stoichiometric relation 1" x "stoichiometric relation 2"
*Unknown variable = atoms of Carbon
*Data = 1 g of Carbon
*Stoichiometric relation 1 = [tex]\frac{1 mol of Carbon atoms}{12 g of Carbon}[/tex]
*Stoichiometric relation 2 = [tex]\frac{6.022 · 10^{23} of Carbon atoms }{1 mol of Carbon}[/tex]
Then we will replace information in general structure:
atoms of C = [tex]1 g of Carbon x[/tex] [tex]\frac{1 mol of Carbon atoms}{12 g of Carbon} x \frac{6.022 ·10^{23} Carbon atoms}{1 mol of Carbon atoms}[/tex]
atoms of Carbon = 5,0 x [tex]10^{22}[/tex] atoms of Carbon
