Answer: The amount required in grams to reduce the freezing point by 0.500 degree Celsius will be 6.58 g.
Solution: equation to calculate depression in freezing point
[tex]\Delta T_{f}=T_{f} _{solvent}-T_{f} _{solution}=k_{f}\times m[/tex]
given: [tex]\Delta T_{f}[/tex] = 0.500°C
[tex]k_{f}[/tex] = for benzene is 5.12
m=?
y= TNT amount (in grams) required
[tex]m=\frac{\text{given mass}}{\text{molar mass}\times \text{weight of solvent (in gms)}}\times1000[/tex]
[tex]m=\frac{{y}}{227.1\times 297}\times1000[/tex]
now according to formula:
[tex]\Delta T_{f}=k_{f}\times m[/tex]
[tex]0.500=\frac{5.12\times y}{227.1\times 297}\times1000\\y=6.59gms[/tex]
