ok... these are simple if you know what to do.
step 1) swap the x and h(x)
[tex]x = \frac{2h(x) - 4}{3} [/tex]
step 2) rewrite h(x) as inverse of h(x)
[tex]x = \frac{2 {h}^{ - 1}(x) - 4 }{3} [/tex]
step 3) solve for inverse of h(x)
[tex]x = \frac{2 {h}^{ - 1}(x) - 4 }{3} \\ 3x = 2 {h}^{ - 1} ( x) - 4 \\ 3x + 4 = 2 {h}^{ - 1} (x) \\ \frac{3x + 4}{2} = {h}^{ - 1} (x)[/tex]
