The solution is 5.71 % CaCl₂ by mass.
Total mass = 22.7 g + 375 g = 397.7 g
[tex]\%\text{CaCl}_{2} = \frac{\text{Mass of CaCl}_{2}}{\text{Total mass}}\times 100 \%\\[/tex]
[tex]\%\text{CaCl}_{2} = \frac{\text{22.7 g}}{\text{397.7 g}}\times 100 \%\\[/tex]
