We have been given that maximum age for a youth ticket is 18 years old and minimum age is 10 years old.
Our first step is to find average age, that is, mid point of maximum and minimum. That would be [tex]\frac{18+10}{2} =\frac{28}{2}=14[/tex]
Difference between the average (mean) from maximum or minimum is |14-10|=4
Therefore, the required absolute value equation for which two solutions are the maximum and minimum ages for a youth ticket would be:
[tex]|x-14|=4[/tex]
