If you add 43 of food in 350 ml water and dilution of 1:6 is made then from this dilution 1:90 is made and from this 1 ml is added to 60 ml of water then 0.1 ml from this last dilution is plated and after incubation 143 colonies are counted what is the total count per g of original sample

Respuesta :

Solution:

DF = Initial dilution * Subsequent dilution * Amount Plated

Total Count Per g = [tex]\frac{1}{DF}[/tex] * Colonies Counted

Initial dilution : [tex]\frac{43}{(43+350)}=\frac{43}{393}[/tex]

Subsequent dilution : [tex](\frac{1}{6} )*(\frac{1}{90} )*(\frac{1}{61} )[/tex]

Amount Plated : 0.1

Colonies Counted : 143

DF = [tex]\frac{43}{393}*\frac{1}{6}*\frac{1}{90}*\frac{1}{61}*0.1[/tex]

DF=[tex]\frac{43}{393}*\frac{1}{6}*\frac{1}{90}*\frac{1}{61}*\frac{1}{10}[/tex]

DF = [tex]\frac{43}{129454200}[/tex]

Total Count Per g = [tex](\frac{129454200}{43} )*143[/tex]

Total Count Per g = [tex]4.3*10^{8}[/tex]