One common system for computing a grade point average​ (GPA) assigns 4 points to an​ A, 3 points to a​ B, 2 points to a​ C, 1 point to a​ D, and 0 points to an F. What is the GPA of a student who gets an A in a
33​-credit
​course, a B in each of
three

2​-credit
​courses, a C in a
3​-credit
​course, and a D in a
2​-credit
​course?

Respuesta :

GPA = 3.59

For calculating the GPA, first calculate the quality points for each grade and course and then add them up like shown below:

A - 4 points x 33 credit hours = 132 quality points

B - ( 3 points x 2 credit hours ) x 3 (because there are 3 courses) = 18 quality points

C - 2 points x 3 credits = 6 quality points

D - 1 point x 2 credits = 2 quality points

Now add up all the quality points = 132 + 18 + 6 + 2 = 158

Add the credit hours as well = 33 + 6 + 3 + 2 = 44

Divide the total quality points by total credit hours to get the GPA = 158/44 = 3.59

Answer:

The GPA of the student is 3.59

Explanation:

We present the information in the table below.

[tex]\begin{tabular}{|c|c|c|c|} Course Grade & Grade Point (x) & Course Credit(y) & Product(xy) \\$---$ & $---$ & $---$ & $---$ \\$A$ & 4 & 33 & 132 \\$B$ & 3 & 2 & 6 \\$B$ & 3 & 2 & 6 \\$B$ & 3 & 2 & 6 \\$C$ & 2 & 3 & 6 \\$D$ & 1 & 2 & 2 \\$---$ & $---$ & $---$ & $---$ \\Total & & 44 & 158\end{tabular}[/tex]

Therefore, the GPA of the student is:

[tex]GPA=\frac{158}{44}[/tex]

[tex]=3.59[/tex]

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