The correct answer is : Rose cost is 2.1$,
carnation cost is 0.82$ and
tulip cost is 6.06$
Solution:-
Let rose cost be r$, carnation cost be c$ and tulip cost be t$.
Given 3 roses,2 carnations and 1 tulip costs 14$.
That is 3r+2c+t = 14, let it be first equation.
Also given 2 carnations and 6 tulips costs 38$.
That is 2c+6t=38
c+3t=19
c=19-3t
Also 1 rose, 12 carnations and 1 tulip costs 18$.
That is r+12c+t=18
Let us plugin c=19-3t in above equation.
r+12(19-3t)+t = 18
r=35t-210
Let us plugin r and c in first equation.
3(35t-210)+2(19-3t)+t =14
105t-630+38-6t+t =14
100t = 606
t=6.06$
c=19-3*6.06 = 0.82$
r=35*6.06-210=2.1$
