Let the number be 'x'.
According to the question,
[tex]\frac{5}{16}+x = 1 \frac{1}{4} - 1 \frac{1}{8}[/tex]
[tex]\frac{5}{16}+x = \frac{5}{4} -\frac{9}{8}[/tex]
Since, LCM of 4 and 8 is '8'.
[tex]\frac{5}{16}+x = \frac{10-9}{8}[/tex]
[tex]\frac{5}{16}+x = \frac{1}{8}[/tex]
[tex]x = \frac{1}{8} - \frac{5}{16}[/tex]
LCM of 8 and 16 is 16.
[tex]x = \frac{2-5}{16}[/tex]
[tex]x = \frac{-3}{16}[/tex]
Therefore,[tex]\frac{-3}{16}[/tex] is bigger than [tex]\frac{5}{16}[/tex] by the same amount that [tex]1\frac{1}{8}[/tex] is less than [tex]1\frac{1}{4}[/tex].
