[tex]\frac{(x-h)^{2} }{a^{2} } - \frac{(y - k)^{2} }{b^{2} } = 1[/tex]
[tex]\frac{(x-0)^{2} }{40^{2} } - \frac{(y - 0)^{2} }{b^{2} } = 1[/tex]
a² + b² = c²
40² + b² = 41²
b² = 41² - 40²
b² = 1681 - 1600
b² = 81
b = 9
slope (m) of asymptote = [tex]+/-\frac{y}{x} = +/-\frac{b}{a} = +/-\frac{9}{40}[/tex]
y-intercept (b) = 0 since the center is at the origin
Answer: y = [tex]\frac{9}{40}x[/tex] and y = [tex]-\frac{9}{40}x[/tex]
Answer:
y = +/- 40/9 x
NOT 9/40
Step-by-step explanation:
just took the quiz and it was the right answer
