Considering ideal gas behavior, the volume of 1 mol of gas at STP is 22.4 L; then the volume occupied by 1.9 moles is 1.9mol*22.4L/mol
The answer is 43 L if I am correct.
Hello!
For this exercise you have to use the Ideal Gas Law Equation, as follow:
PV= nRT
Where:
P= pressure ( in this example, atmosphere (atm) is the pressure unit)
V= volume (which is the value you want to calculate)
n= Mol (as reference to the mass of the gas Cl2)
R = Ideal Gas Constant (for this example is a number 0.0821 atm*L/mol*K)
T= Temperature in Kelvin (K)
So, for find the value of the volume, you just have to replace the values given in the equation as follow:
P= 1.3 atm
V = you don't know, is what you want to know.
n= 1.9 mol
R =0.0821 atmL/molK
T =298 K
Remember, never forget to put the units, because teacher can get down your score if you don't do it. So, back with the values to the equation:
13atm * V = 1.9mol * 0.0821 atmL/molK * 298K
Then, we have to solve the equation to find V value, so we has to send 1.3 atm to divide in the other side of the equation:
V = (1.9mol * 0.0821 atmL/molK * 298K)/ 1.3 atm
V = 35.76 L
And, that's it!
I hope this help you a lot, and good luck.
