Respuesta :

plbak

In order to find the answer to this problem, we would need to complete the punnet square, which will allow us to see the possibility of having female offspring. Which I have attached!

The possibility then of having female offspring is 50% (due to the chromosomes XX)

Referring back to the original form of the punnet square we see that one parent has both dominant alleles and does not carry the recessive trait, where as the other does. This being said, when it is passed down the offspring it will have a mix of both the dominant and recessive gene. Though it will carry the gene, it will not be able to have the disease.

So the answer to your question is no!




Ver imagen plbak

It is not possible for a female to have the disease. Recessive disease  only occur when offspring gets both alleles.

The  Punnett square is,

            [tex]\bold {X^r}[/tex]               Y

[tex]\bold {X^R}[/tex]      [tex]\bold {X^R}[/tex][tex]\bold {X^r}[/tex]       [tex]\bold {X^R}[/tex]Y

[tex]\bold {X^R}[/tex]       [tex]\bold {X^R}[/tex][tex]\bold {X^r}[/tex]      [tex]\bold {X^R}[/tex]Y

Given here,

The disease is recessive Hence it is only occur when offspring gets both alleles.

In the punnet square both female offspring has one dominant and one recessive alleles.

Therefore, no female offspring will express the disease gene.

To know more about X-linked recessive disease,

https://brainly.com/question/16014908

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