The equation y=x^3 + 3 is symmetric with respect to which of he following?
a. The y-axis
b. The line y = x + 3
c. The point (0,3)
d. The x-axis

Respuesta :

[tex]y = x^{3} +3[/tex]

Subtract 3 from both sides,

[tex]y-3=x^{3}[/tex]

Let x = X and y - 3 = Y

Then,

[tex]Y = X^{3}[/tex]

So, we have shifted the origin to a point (0, 3).

This is an odd function and the graph of an odd function is symmetrical about the origin.

That is, symmetrical about X = 0, Y = 0

Symmetrical about x = 0,, y - 3 = 0

Symmetrical about x = 0, y = 3.

Hence, the graph is symmetrical about the point (0, 3).

Answer:

c. the point (0,3)

Step-by-step explanation: