What is the solution to the above system of equations?

(x , y) = (7, - 1)
2x + 3y = 11 → (1)
3x + 3y = 18 → (2)
subtracting (1) from (2) term by term eliminates the y- term
(3x - 2x) + (3y - 3y) = (18 - 11)
x + 0 = 7 ⇒ x = 7
substitute x = 7 into either of the 2 equations and solve for y
(1) → (2 × 7) + 3y = 11
14 + 3y = 11
subtract 14 from both sides
3y = 11 - 14 = - 3
divide both sides by 3
[tex]\frac{- 3}{3}[/tex] = - 1
solution is (7 , -1)
The solution to the system of equations are x = 7 and y = -1
2x + 3y = 11 equation 1
3x + 3y = 18 equation 2
The equations given are simultaneous equations. They would be solved using the elimination method.
In order to use the elimination method, take the following steps:
1. Subtract equation 1 from equation 2
x = 7
2. Substitute for x in equation 1
2(7) + 3y = 11
3. Expand the bracket
14 + 3y = 11
4. Combine similar terms
3y = 11 - 14
5. Add similar terms
3y = -3
6. Divide both sides of the equation by 3
y = - 1
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